*fan and medal awarded* Factor completely: 2x^3y^4 âˆ’ 8x^2y^3 + 6xy^2 2(x^3y^4 âˆ’ 4x^2y^3 + 3xy^2) 2x(x^2y^4 âˆ’ 4xy^3 + 3y^2) 2xy^2(x^2y^2 âˆ’ 4xy + 3) Prime

well what can be taken out of each term? each number is divisable by 2 right?? so that can be taken out there's at least 1 x in each term right? so that can be taken out there's at least 1 y in each term right? so THAT can be taken out so we have 2xyÂ²(xÂ²yÂ² - 4xy + 3) :)

can u help with a few more ?

absolutely :) if i can :P

Factor completely: 3x âˆ’ 12 3(x âˆ’ 4) 3(x + 4) 3x(âˆ’12) Prime

okay...same thing here what can be taken out of both terms? both numbers are divisable by 3 right so that can be taken out 3(x - 4)

What is the Greatest Common Factor of 12 and 36? 2 4 6 12 i tihnk its 6

*think

...well...is 12 divisable by 12? yes is 36 divisable by 12?

yess 3

...well we don't actually need how much it is divisable by...as long as it IS....so since 12 goes into both 12 and 36..the answer is?

ooh 12. lol my bad

Factor completely: âˆ’3x2 + 6x âˆ’ 9 âˆ’3(x2 âˆ’ 2x + 3) âˆ’1(x2 âˆ’ 6x + 9) âˆ’3x(x2 âˆ’ 2x + 3) âˆ’3(x2 + 2x âˆ’ 3)

âˆ’3x(x2 âˆ’ 2x + 3) right ?

close.....you got that 3 can come out of each term....but you also said that x can come out of all the terms.....is there an x with the 9?

reworder: can you take an x from just 9?

nope

okay...so there is no x taken out...but -3 yes so -3(xÂ² - 2x + 3)

thank u !!! i got a 100 :)

haha that's what you want :) anytime :)

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