OpenStudy (anonymous):

*fan and medal awarded* Factor completely: 2x^3y^4 − 8x^2y^3 + 6xy^2 2(x^3y^4 − 4x^2y^3 + 3xy^2) 2x(x^2y^4 − 4xy^3 + 3y^2) 2xy^2(x^2y^2 − 4xy + 3) Prime

5 years ago
OpenStudy (johnweldon1993):

well what can be taken out of each term? each number is divisable by 2 right?? so that can be taken out there's at least 1 x in each term right? so that can be taken out there's at least 1 y in each term right? so THAT can be taken out so we have 2xy²(x²y² - 4xy + 3) :)

5 years ago
OpenStudy (anonymous):

can u help with a few more ?

5 years ago
OpenStudy (johnweldon1993):

absolutely :) if i can :P

5 years ago
OpenStudy (anonymous):

Factor completely: 3x − 12 3(x − 4) 3(x + 4) 3x(−12) Prime

5 years ago
OpenStudy (johnweldon1993):

okay...same thing here what can be taken out of both terms? both numbers are divisable by 3 right so that can be taken out 3(x - 4)

5 years ago
OpenStudy (anonymous):

What is the Greatest Common Factor of 12 and 36? 2 4 6 12 i tihnk its 6

5 years ago
OpenStudy (anonymous):

*think

5 years ago
OpenStudy (johnweldon1993):

...well...is 12 divisable by 12? yes is 36 divisable by 12?

5 years ago
OpenStudy (anonymous):

yess 3

5 years ago
OpenStudy (johnweldon1993):

...well we don't actually need how much it is divisable by...as long as it IS....so since 12 goes into both 12 and 36..the answer is?

5 years ago
OpenStudy (anonymous):

ooh 12. lol my bad

5 years ago
OpenStudy (anonymous):

Factor completely: −3x2 + 6x − 9 −3(x2 − 2x + 3) −1(x2 − 6x + 9) −3x(x2 − 2x + 3) −3(x2 + 2x − 3)

5 years ago
OpenStudy (anonymous):

−3x(x2 − 2x + 3) right ?

5 years ago
OpenStudy (johnweldon1993):

close.....you got that 3 can come out of each term....but you also said that x can come out of all the terms.....is there an x with the 9?

5 years ago
OpenStudy (johnweldon1993):

reworder: can you take an x from just 9?

5 years ago
OpenStudy (anonymous):

nope

5 years ago
OpenStudy (johnweldon1993):

okay...so there is no x taken out...but -3 yes so -3(x² - 2x + 3)

5 years ago
OpenStudy (anonymous):

thank u !!! i got a 100 :)

5 years ago
OpenStudy (johnweldon1993):

haha that's what you want :) anytime :)

5 years ago