Question

*fan and medal awarded*

Factor completely: 2x^3y^4 − 8x^2y^3 + 6xy^2
2(x^3y^4 − 4x^2y^3 + 3xy^2)
2x(x^2y^4 − 4xy^3 + 3y^2)
2xy^2(x^2y^2 − 4xy + 3)
Prime

Answer 1

well what can be taken out of each term?
each number is divisable by 2 right?? so that can be taken out

there's at least 1 x in each term right? so that can be taken out
there's at least 1 y in each term right? so THAT can be taken out

so we have

2xy²(x²y² - 4xy + 3) :)

Answer 2

can u help with a few more ?

Answer 3

absolutely :) if i can :P

Answer 4

Factor completely: 3x − 12

3(x − 4)

3(x + 4)

3x(−12)

Prime

Answer 5

okay...same thing here
what can be taken out of both terms?
both numbers are divisable by 3 right so that can be taken out
3(x - 4)

Answer 6

What is the Greatest Common Factor of 12 and 36?

2

4

6

12
i tihnk its 6

Answer 7

*think

Answer 8

...well...is 12 divisable by 12? yes

is 36 divisable by 12?

Answer 9

yess 3

Answer 10

...well we don't actually need how much it is divisable by...as long as it IS....so since 12 goes into both 12 and 36..the answer is?

Answer 11

ooh 12. lol my bad

Answer 12

Factor completely: −3x2 + 6x − 9

−3(x2 − 2x + 3)

−1(x2 − 6x + 9)

−3x(x2 − 2x + 3)

−3(x2 + 2x − 3)

Answer 13

−3x(x2 − 2x + 3) right ?

Answer 14

close.....you got that 3 can come out of each term....but you also said that x can come out of all the terms.....is there an x with the 9?

Answer 15

reworder: can you take an x from just 9?

Answer 16

nope

Answer 17

okay...so there is no x taken out...but -3 yes

so -3(x² - 2x + 3)

Answer 18

thank u !!! i got a 100 :)

Answer 19

haha that's what you want :) anytime :)