I'm studying for two important tests and I generated a few questions for me to solve but I need to know how to do this properly. Divide (6y3 - 2y2) by (3y - 1).

Question

I'm studying for two important tests and I generated a few questions for me to solve but I need to know how to do this properly.  Divide (6y3 - 2y2) by (3y - 1).

anonymous · Answer

well first see if you can factor out anything

anonymous · Answer

Factor out 2y2 from the equation 6y3-2y2. You are supposed to get 2y2(3y-1) divided by 3y-1. Then the two 3y-1 cancel. You are left with 2y2. That is your answer... hope i helped.. :)

anonymous · Answer

how are you suppose to find the y?

anonymous · Answer

wait you need to solve it?

anonymous · Answer

yes I'm suppose to divide it.

anonymous · Answer

i don't think you need to find the y. Because if u are then your question was supposed to be an equation not an expression..

anonymous · Answer

Oh I see. that's true. so how am I suppose to know which parts to cancel out?

directrix · Answer

@Geometrythebest 

Are you practicing long division, simplification, or something else?