I'm studying for two important tests and I generated a few questions for me to solve but I need to know how to do this properly. Divide (6y3 - 2y2) by (3y - 1).

well first see if you can factor out anything

Factor out 2y2 from the equation 6y3-2y2. You are supposed to get 2y2(3y-1) divided by 3y-1. Then the two 3y-1 cancel. You are left with 2y2. That is your answer... hope i helped.. :)

how are you suppose to find the y?

wait you need to solve it?

yes I'm suppose to divide it.

i don't think you need to find the y. Because if u are then your question was supposed to be an equation not an expression..

Oh I see. that's true. so how am I suppose to know which parts to cancel out?

@Geometrythebest Are you practicing long division, simplification, or something else?

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