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Find the norm of vector r prime of t when r(t) = t^2i + 2sintj + 2costk
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r'(t)=? r(t) is given
so start with taking derivative
then square each component , add them
take square root
\[\sqrt(4t^2 + 4\cos^2t + 4\sin^2t)\]
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What's the trig identity for cos and sin?
cos^2 t + sin^2 t =1
so does the second half of that just become 8?
4( 1)=4
Can you explain? I can never follow this one...
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cos(t)^2+sin(t)^2=1 4(cos(t)^2+sin(t)^2)=4
Ohhhh.... Is that technically combining like terms?
I guess
Thanks!
no problem
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