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OpenStudy (anonymous):
how do I prove 2tanx/sinx=cscxtanx+secx

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OpenStudy (anonymous):
tan(x)/sin(x)= sec(x)

OpenStudy (anonymous):
so this is 2 sec(x)

OpenStudy (anonymous):
so we have to prove csc x tan(x) = sec(x)
1/sin(x) * sin(x)/cos(x)= 1/cos(x)= sec(x)

OpenStudy (anonymous):
How did you get tan(x)/sin(x)= sec(x)

OpenStudy (anonymous):
tan(x)= sin(x)/cos x
sin x / cos x * 1/ sin(x)
sin(x) cancels , leaving 1/cos x = sec x

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OpenStudy (anonymous):
oh ok

OpenStudy (anonymous):
oh I see the answer. thank you.

OpenStudy (anonymous):
wait, wouldn't sinx / cos x be multipy by sinx not 1/sinx

OpenStudy (anonymous):
why

OpenStudy (anonymous):
because the sinx is on the denominator and when you do the reciprocial 1/sinx it's sinx

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OpenStudy (anonymous):
because the sinx is on the denominator and when you do the it is reciprocial 1/sinx
fixed

OpenStudy (anonymous):
fixed? what?

OpenStudy (anonymous):
divide is same as multiplication by it reciprocal
so we dividing by sin(x)
that's same as multiplying by
1/sin x

OpenStudy (anonymous):
oh ok. I understand

OpenStudy (anonymous):
thanks for your help.

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OpenStudy (anonymous):
you are welcome

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