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OpenStudy (anonymous):

Calculus challenge

OpenStudy (anonymous):

The type of bread chosen for this special calculus toast isn't the square sandwich shape, but the kind that is curved across the top. Imagine that the toast is composed of the curved part sitting atop the rectangular portion. The equation of the curved part of the toast is x2/4 + y2 = 1, and it sits directly and perfectly on top of a rectangle of height 3 inches. a) What are the equations of the rectangular boundaries? b) Graph the toast boundaries, making certain to include screen shots of the boundary equations, Window settings, and the graph. c) How would you find the length of the curve

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then

OpenStudy (anonymous):

once you find two x values , they are your answer for a)

OpenStudy (anonymous):

is x two negative values

OpenStudy (anonymous):

is x squred?

OpenStudy (anonymous):

ya here is the equation again \[\frac{ x^2 }{ 4 } + y^2 = 1\]

OpenStudy (anonymous):

ahh, that's different, this is ellipse x^2/4 + (y-3)^2 = 1

OpenStudy (anonymous):

now plug in y=3, x^2/4=1 x^2=4 x=2,-2 that's your part a

OpenStudy (anonymous):

sweet ur r doing grt go ahead

OpenStudy (anonymous):

part b is graphing,

OpenStudy (anonymous):

Here's the graph, done without benefit of the above

OpenStudy (anonymous):

i wud just graph that right

OpenStudy (anonymous):

oh thx @dlipson1 can u go further

OpenStudy (anonymous):

Uh oh, I think that's a line integral, I'd have to look that up. Do you know anything about Stochastic Optimization?

OpenStudy (anonymous):

hey hey hey never mind...i know how to find the length of the curve thanks..but i dont knw do i need to find length of whole curve or just the bread as in ur graph

OpenStudy (anonymous):

Well, the rectangle is trivial (is the side along the x-axis included?), the top is just half the ellipse, that's the only real calculus (integration) you have to do.

OpenStudy (anonymous):

so from negative 2 to 2...right

OpenStudy (anonymous):

Yeah, use the top half, y = sqrt(...), then (I just looked it up): Length = integral (sqrt(1+(y')^2))dy

OpenStudy (anonymous):

ya and what kinda graphing calculator r u using dude

OpenStudy (anonymous):

thx...getting my next question...i wud give u a lot of awards but unfortunately this site doesnt aloow lol

OpenStudy (anonymous):

"Graph" (from padowan.dk) gives me the curve length of 4.882, then +3+3 +4 for the entire perimeter.

OpenStudy (anonymous):

sweet thanks

OpenStudy (anonymous):

hey @dlipson1 one more thing, how wud we find area on top of the toast

OpenStudy (anonymous):

The rectangle + 2*integral (by symmetry) from 0 to 2 of y = sqrt(1-x^2/4)... hmm, do we need substitution here?

OpenStudy (anonymous):

do u need the derivative...i have it

OpenStudy (anonymous):

-x/(4y-12)....now wht to do

OpenStudy (anonymous):

I'm not sure dy/dx helps. I set up the integral, thought about a trig. substitution, multiplied through by the 2 (as sqrt(4)) to get int(sqrt(4-x^2))dx, which I found here, but I think there must be an easier way (like polar coordinates): http://answers.yahoo.com/question/index?qid=20071231235113AAAAfuP

OpenStudy (anonymous):

Here is almost the same problem: http://www.youtube.com/watch?v=PSlsj0IP8R8

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