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Mathematics 8 Online
OpenStudy (anonymous):

how do I find the identity to: csc^3xcot^2x-cot^2x

OpenStudy (anonymous):

csc^2 or csc^3

OpenStudy (anonymous):

if it is csc^3 . it's is cot^4x cscx

OpenStudy (anonymous):

csc^3

OpenStudy (anonymous):

that 's what i have

OpenStudy (anonymous):

how are you getting cot^4x

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