write 3ab^-2c^-1 with positive exponents
\[10x ^{-2}=\frac{10}{x ^{2}}\] You can make use of this rule.
i don't get it
\[\sqrt[3]{xy^2}\]
i am totally baffles by the one above too,,,
To eliminate the negative exponent of x I used the following process: \[10x ^{-2}=\frac{10x ^{-2}}{1}\] Next multiply the numerator an the denominator of the fraction by x^2 \[\frac{10x ^{-2}\times x ^{2}}{x ^{2}}=\frac{10x ^{0}}{x ^{2}}=\frac{10}{x ^{2}}\]
where did u get the 10 x to start with???
The choice of 10x^-2 was just an example of the process to eliminate a negative exponent (without actually giving the answer to your question).
Good!
3ab/1 -2 oh sisgh
what do u do with the exta exponents?
is it just 3 over all the variables?
\[3ab ^{-2}c ^{-1}=\frac{3a}{b ^{2}c}\]
oh becaause the a doesn't have an exponet,,
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