Question

If f'(x) = sin [(π×e^x) / 2] and f(0) = 1, then f(2) = (A) -1.819 (B) -0.843 (C) -0.819 (D) 0.157 (E) 1.157

Answer 1

integrate f'(x) and substitute 0 in it

Answer 2

How do I integrate it though?

Answer 3

w8
wirting the solution

Answer 4

u know the substitution method?

Answer 5

Yes i do. i think i figured it out. Thanks!

Answer 6

substitute u=\[\frac{ \pi*e^x }{ 2 }\]

Answer 7

\[\frac{ du }{ dx }=\frac{ x }{ 2 \pi*e^x }\]

Answer 8

\[dx=\frac{ 2u }{ xpi*e^x }\]

Answer 9

(-2 cos((1/2 pi e^x)/(x pi e^x))) / (x pi e^x)

Answer 10

That's great. I got it. Thank you!!