What is the formula for the ions that are present when coh4 is dissolved in water
what is that compound formula can u rewrite it
CH3OH .. that what you mean?
yaaaaa got it
I did NaOH as \[Na ^{+}+ OH ^{-}\]SO4H2 as\[2 H _{3}O ^{+} + SO _{4}^{2-}\]and ClO4H as\[H ^{+}+ClO _{4}^{-}\]But I don't know if they're right and I don't know how to do COH4...
in case of methanol its difficult to do that bcoz its not so ionic as NaOH and Ohters and CH3OH is organic compound but still some ions may exist like CH3OH2+ and H3O+ but very less
so then what ions are there if you dissolve it in water? I don't understand this
would it be co + 2 h2??? =/ I'm so confused
no ions will be there pure CH3OH and water will be present with some vandewall s interaction between them
CO+2H2 are u saying
it will give rise to CH3OH
hmmmm :( I don't understand this... we haven't talked about that
COH4 + 4 H2O = 4 H3O + CO this would be the balanced equation right??? so you're left with CO and H3O... are those not ions?
no they are not ions ,ions should have charge right!! do they have charge!!!!
guess not. Lol. I'm so tired and this isn't making sense. I think I should go to bed and try again tomorrow!!!!!
wait .. but I thought hydronium does have a charge? If it doesn't, is my answer for SO4H2 wrong?
CH3OH <-> CH3O- + H+ ( H+ is really H3O+) and should be written as CH3OH + H2O <-> H3O+ + CH3O-
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