Question

What is the formula for the ions that are present when coh4 is dissolved in water

Answer 1

what is that compound formula can u rewrite it

Answer 2

CH3OH .. that what you mean?

Answer 3

yaaaaa got it

Answer 4

I did NaOH as \[Na ^{+}+ OH ^{-}\]SO4H2 as\[2 H _{3}O ^{+} + SO _{4}^{2-}\]and ClO4H as\[H ^{+}+ClO _{4}^{-}\]But I don't know if they're right and I don't know how to do COH4...

Answer 5

in case of methanol its difficult to do that bcoz its not so ionic as NaOH and Ohters and CH3OH is organic compound
but still some ions may exist like CH3OH2+ and H3O+ but very less

Answer 6

so then what ions are there if you dissolve it in water? I don't understand this

Answer 7

would it be co + 2 h2??? =/ I'm so confused

Answer 8

no ions will be there pure CH3OH and water will be present with some vandewall s interaction between them

Answer 9

CO+2H2 are u saying

Answer 10

it will give rise to CH3OH

Answer 11

hmmmm :( I don't understand this... we haven't talked about that

Answer 12

COH4 + 4 H2O = 4 H3O + CO this would be the balanced equation right??? so you're left with CO and H3O... are those not ions?

Answer 13

no they are not ions
,ions should have charge right!!
do they have charge!!!!

Answer 14

guess not. Lol. I'm so tired and this isn't making sense. I think I should go to bed and try again tomorrow!!!!!

Answer 15

wait .. but I thought hydronium does have a charge? If it doesn't, is my answer for SO4H2 wrong?

Answer 16

CH3OH <-> CH3O- + H+ ( H+ is really H3O+)

and should be written as

CH3OH + H2O <-> H3O+ + CH3O-