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Chemistry 7 Online
OpenStudy (anonymous):

What is the formula for the ions that are present when coh4 is dissolved in water

OpenStudy (chmvijay):

what is that compound formula can u rewrite it

OpenStudy (anonymous):

CH3OH .. that what you mean?

OpenStudy (chmvijay):

yaaaaa got it

OpenStudy (anonymous):

I did NaOH as \[Na ^{+}+ OH ^{-}\]SO4H2 as\[2 H _{3}O ^{+} + SO _{4}^{2-}\]and ClO4H as\[H ^{+}+ClO _{4}^{-}\]But I don't know if they're right and I don't know how to do COH4...

OpenStudy (chmvijay):

in case of methanol its difficult to do that bcoz its not so ionic as NaOH and Ohters and CH3OH is organic compound but still some ions may exist like CH3OH2+ and H3O+ but very less

OpenStudy (anonymous):

so then what ions are there if you dissolve it in water? I don't understand this

OpenStudy (anonymous):

would it be co + 2 h2??? =/ I'm so confused

OpenStudy (chmvijay):

no ions will be there pure CH3OH and water will be present with some vandewall s interaction between them

OpenStudy (chmvijay):

CO+2H2 are u saying

OpenStudy (chmvijay):

it will give rise to CH3OH

OpenStudy (anonymous):

hmmmm :( I don't understand this... we haven't talked about that

OpenStudy (anonymous):

COH4 + 4 H2O = 4 H3O + CO this would be the balanced equation right??? so you're left with CO and H3O... are those not ions?

OpenStudy (chmvijay):

no they are not ions ,ions should have charge right!! do they have charge!!!!

OpenStudy (anonymous):

guess not. Lol. I'm so tired and this isn't making sense. I think I should go to bed and try again tomorrow!!!!!

OpenStudy (anonymous):

wait .. but I thought hydronium does have a charge? If it doesn't, is my answer for SO4H2 wrong?

OpenStudy (aaronq):

CH3OH <-> CH3O- + H+ ( H+ is really H3O+) and should be written as CH3OH + H2O <-> H3O+ + CH3O-

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