Choose one of the factors of 24x6 – 1029y3

3

2x2 – 7y

4x4 + 14x2y + 49y2

All of the above

Question

Choose one of the factors of 24x6 – 1029y3

 3

 2x2 – 7y

 4x4 + 14x2y + 49y2

 All of the above

ajprincess · Answer

$\Large24x^6-1029y^3=3*2^3(x^2)^3-3*(3^2)^3y^3$
                         $\Large=3*(2x^2)^3-3(3^2y)^3$
                         $\Large=3*(2x^2)^2-3*(9y)^3$
$\Large(a^3-b^3)=(a-b)(a^2+ab+b^2)$
Does that help?

anonymous · Answer

one number finishes in 9 so the only factors will be 3 and 9, 
but 9 is not a factor of 24, so you're only left with 3 .
since no variables are common to both .
 the common factor is only 3