Question

Choose one of the factors of 24x6 – 1029y3

3

2x2 – 7y

4x4 + 14x2y + 49y2

All of the above

Answer 1

\(\Large24x^6-1029y^3=3*2^3(x^2)^3-3*(3^2)^3y^3\)
\(\Large=3*(2x^2)^3-3(3^2y)^3\)
\(\Large=3*(2x^2)^2-3*(9y)^3\)
\(\Large(a^3-b^3)=(a-b)(a^2+ab+b^2)\)
Does that help?

Answer 2

one number finishes in 9 so the only factors will be 3 and 9,
but 9 is not a factor of 24, so you're only left with 3 .
since no variables are common to both .
the common factor is only 3