Differentiate the function; H(y)=(y^3+6y^2-11y+36)(y^2-y+17)
yuk. This just a product of two functions. So use the product rule. The product rule says if f and g are functions of x(or y in this case), then (fg)'=f'g+g'f where f and g and f' and g' are function in y.
Alternatively, you can go about this using logarithmic differentiation. Given a function \(y=f(x)g(x),\) you take the log of both sides and differentiate: \[\ln(y)=\ln(f(x)g(x))\\ \ln(y)=\ln(f(x))+\ln(g(x))\\ \frac{y'}{y}=\frac{f'(x)}{f(x)}+\frac{g'(x)}{g(x)}\\ y'=f(x)g(x)\left[\frac{f'(x)}{f(x)}+\frac{g'(x)}{g(x)}\right]\] This method may be handier if you're given the product of more than two functions that have simple derivatives. For example, \(\large \displaystyle y=(x+9)(x-8)(x+7)(x-6)(\cdots)\)
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