Question

solve and check extraeous solution
3square root 2x+4=12

Answer 1

[3\sqrt{2x+4=12}\]
divide by 3
\[\sqrt{2x+4} = 4\]
multiply both sides 2 as exponent.
it will become
2x +4 = 4\[^{2}\]
2x +4 = 16
2x = 16-4
2x = 12
divide by 2
x= 6

Answer 2

can u do another?

Answer 3

^ Ask away