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OpenStudy (anonymous):
A 0.09 kg bullet is fired from a 64 kg rifle with a muzzle speed of 300 m/s. What is the speed of the rifle recoil?
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OpenStudy (anonymous):
that one heavy rifle!
OpenStudy (anonymous):
the bullet's not so small either
OpenStudy (anonymous):
just a problem given by prof -_-
OpenStudy (anonymous):
solution is conservation of momentum ie the momentum of the discharged bullet is equal to the momentum of the rifle. right??
OpenStudy (ghazi):
under ideal conditions you are supposed to obey conservation of linear momentum so based on that , momentum of bullet = momentum of rifle due to recoil speed \[0.09*300=64*v\] therefore \[v=\frac{ 0.09*300 }{ 64 } m/s\]
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