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OpenStudy (anonymous):
The equation motion of a particle is s =t^4-2t^3+t^2-t where s is in meters and t is in seconds. find the ACCELERATION at t = 1 second including units.
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OpenStudy (anonymous):
the first derivative of a particle in space with respect to time is velocity the second derivative of a particle in space with respect to time is acceleration just find the 2nd derivative and substitute for t=1 second
OpenStudy (anonymous):
Okayy...so would the first derrivative be 4t^3-6t^2+2t-1 then the second being 12t^2-12t+1 Then substituting the one would the answer be 1 meter per second?
OpenStudy (anonymous):
units are incorrect acceleration is meters per second squared - m/s^2 velocity is meters per second - m/s
OpenStudy (anonymous):
Ohh, Okayy! Well Thank you very much! :)
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