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Mathematics 47 Online
OpenStudy (anonymous):

Factor: 3x^2z+36xz+96z

Parth (parthkohli):

First, factor the 3 out. What do you get?

OpenStudy (anonymous):

x^2z+12xz+32

Parth (parthkohli):

\[x^2 z + 12xz + 32z\]Yeah.

hartnn (hartnn):

factor the "3z" out

Parth (parthkohli):

That is what you get inside the bracket.

Parth (parthkohli):

...

Parth (parthkohli):

Now, do you see something common?

Parth (parthkohli):

@jbell2012

OpenStudy (anonymous):

that i need to factor the 3 out?

hartnn (hartnn):

didn't you already do that ? infact, '3z' was common to all terms, so you could have factor out 3z in first step only.

OpenStudy (anonymous):

yes i did.

OpenStudy (anonymous):

now how do i factor it do to put it in parenthesis? would it be: (xz-8z)(x-4)?

hartnn (hartnn):

lets go step by step ? what you got after factoring out 3z ?

hartnn (hartnn):

so, that i can show you why its not -8 and -4

OpenStudy (anonymous):

i got x^2z-12xz+32z

hartnn (hartnn):

thats only after factoring out 3, right ? after factoring 'z' also, we get 3z (x^2+12x+32) *also, how did '+' in middle change to '-'? :O *

Parth (parthkohli):

It's called magic!

OpenStudy (anonymous):

alright. i see.

hartnn (hartnn):

now can you factor, (x^2+12x+32) ?

OpenStudy (anonymous):

(x+8)(x+4)

hartnn (hartnn):

that would be correct :) so, finally, 3x^2z+36xz+96z would be factored to 3z(x+8)(x+4)

OpenStudy (anonymous):

ALRIGHT! :D now i see this! :P help me with another?

hartnn (hartnn):

sure :) how about a new post , maybe ?

OpenStudy (anonymous):

alright

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