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OpenStudy (anonymous):

how to find the area between y=sinx, y=cosx, y=0 between {0,pi/2} ans: 2-sqrt2

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OpenStudy (goformit100):

@marcleclair

OpenStudy (anonymous):

Cant you find the middle point? Then solve using two integrals?

OpenStudy (anonymous):

i tried that.

OpenStudy (anonymous):

I mean they should intersect at pi/6 ( where they have the same value) --> unit circle I believe ( I don't remember so much)

OpenStudy (anonymous):

sqrt2/2

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OpenStudy (anonymous):

and this is calc II

OpenStudy (anonymous):

Yeah and then integrate both int ( pi/6 - sinx ) + int ( cos x - pi/6) no? Yeah I'm taking cal II too ( well in quebec, might be different curiculum)

OpenStudy (anonymous):

I think im totally wrong though x.x I was just trying to help. Sorry if im mistaken

OpenStudy (anonymous):

what are you trying to do?

OpenStudy (anonymous):

calculus or regular

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OpenStudy (anonymous):

calc 2

OpenStudy (anonymous):

finding the area between 0, sinx and cosx on the interval of 0,pi/2

OpenStudy (anonymous):

|dw:1363164661036:dw|

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