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OpenStudy (anonymous):
how to find the area between y=sinx, y=cosx, y=0 between {0,pi/2} ans: 2-sqrt2
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OpenStudy (goformit100):
@marcleclair
OpenStudy (anonymous):
Cant you find the middle point? Then solve using two integrals?
OpenStudy (anonymous):
i tried that.
OpenStudy (anonymous):
I mean they should intersect at pi/6 ( where they have the same value) --> unit circle I believe ( I don't remember so much)
OpenStudy (anonymous):
sqrt2/2
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OpenStudy (anonymous):
and this is calc II
OpenStudy (anonymous):
Yeah and then integrate both int ( pi/6 - sinx ) + int ( cos x - pi/6) no? Yeah I'm taking cal II too ( well in quebec, might be different curiculum)
OpenStudy (anonymous):
I think im totally wrong though x.x I was just trying to help. Sorry if im mistaken
OpenStudy (anonymous):
what are you trying to do?
OpenStudy (anonymous):
calculus or regular
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OpenStudy (anonymous):
calc 2
OpenStudy (anonymous):
finding the area between 0, sinx and cosx on the interval of 0,pi/2
OpenStudy (anonymous):
|dw:1363164661036:dw|
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