FIND THE EQUATION OF A CIRCLE,DIAMETER AB,WHERE A=(1,3) AND B=(3,7)

What is the length of segment AB where A=(1,3) AND B=(3,7)?

Did you get 2√5 for AB ? @lissafi

The standard form for the equation of a circle is: (x - h) ^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and the radius is r.

If the diameter is 2√5, then the radius is √5. Now, we need the center of the circle.

The center will be the midpoint of the diameter A=(1,3) AND B=(3,7).

The midpoint coordinates of a segment are the average of the x-coordinates and y-coordinates of the endpoints, in this case, of segment AB.

the question just said: find the equetion of the circle satisfying the given condition.Diameter AB, where A=(1,3) AND B=(3,7)

Right. To find that equation, we have to know the radius of the circle.

Also, we have to know the center of the circle.

We need to know how far it is from A to B. I got 2√5. Did you check it to see if I got the right answer?

The midpoint of segment AB is (2,5) which means the point (2,5) is the center of the circle.

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