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Mathematics 16 Online
OpenStudy (anonymous):

l x+4 l = 3x

OpenStudy (tkhunny):

@ryan123345 You just ignored the absolute values. Very bad. The fact that you fond a solution is a coincidence, not an accomplishment.

OpenStudy (anonymous):

Modulus behaves like this... mod(x) = +x , if x>0 and -x , if x<0 For your case check the cases x+4 >0 and x+4 <0... In Your particular question x+4<0 yields us no solution...

OpenStudy (anonymous):

There are two solutions for this question x + 4 = 3x 4 = 2x x = 2 and x + 4 = -3x 4 = -4x x = -1

OpenStudy (tkhunny):

@ritez You ignored the fact that x = -1 is NOT a solution.

OpenStudy (anonymous):

x=-1 is NOT the solution ... because it was calculated using x+4<0...

OpenStudy (anonymous):

i was going to say it further, yes x = -1 does not exist

OpenStudy (tkhunny):

It would have been perfect if you had included the restrictions. IF x + 4 >= 0 or x >= -4 x + 4 = 3x 4 = 2x x = 2 2 >= -4, so this is a solution or IF x < -4 x + 4 = -3x 4 = -4x x = -1 -1 > -4, so this is NOT a solution.

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