Ask your own question, for FREE!
Geometry 24 Online
OpenStudy (anonymous):

A triangle has two sides of length 6 and 6. What value could the length of the third side be? Check all that apply. A. 36 B. 12 C. 10 D. 6 E. 3 F. 2

hartnn (hartnn):

length of 3rd side of a triangle cannot be greater than sum of 2 sides, so, the length less than or = 6+6 does this help ?

OpenStudy (anonymous):

All the possible side lengths fit the following equation: \[(Side A Length) + (Side B Length)\ge (Side C Length)\]

OpenStudy (anonymous):

It helps a lot thank you both

OpenStudy (anonymous):

I think

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

OOPS! Should be less than or equal to. Sorry!

hartnn (hartnn):

also, since i notice you are new here, i would like to welcome you. \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\)

OpenStudy (anonymous):

Welcome as well!

terenzreignz (terenzreignz):

@hartnn did you mean greater than or =?

OpenStudy (anonymous):

I meant less than or equal to

terenzreignz (terenzreignz):

Something about your first post feels kind of reversed...

OpenStudy (anonymous):

I screwed up

hartnn (hartnn):

:O how did i make such a mistake!! i am sorry! its gretaer than =

terenzreignz (terenzreignz):

I am content in the proof that @hartnn is human after all XD

OpenStudy (anonymous):

No worries

OpenStudy (anonymous):

Wait I screwed up again My first answer was right

terenzreignz (terenzreignz):

Or... I screwed up.

terenzreignz (terenzreignz):

I should have stayed mum XD

hartnn (hartnn):

don't over think, The sum of the lengths of any two sides of a triangle always exceeds the length of the third side, a principle known as the triangle inequality

OpenStudy (anonymous):

No... I didn't screw up. \[6+6\neq12\]

OpenStudy (anonymous):

Would indicate I was wrong. Since that equation is in and of itself wrong, I must be right.

OpenStudy (anonymous):

Im learning this stuff in my geometry class and i cant learn because of a first year teacher

OpenStudy (anonymous):

Hmm. I had a first-year teacher and she was fantastic.

OpenStudy (anonymous):

This one is a young guy. He is still acting like a child

OpenStudy (anonymous):

Ah. That could be a problem.

OpenStudy (anonymous):

Yeah and he's a handsome guy and he is distracted by getting alot of attention frow the girls in the class

terenzreignz (terenzreignz):

Getting a bit off topic ;) Let's be general, then :D If you're given two side lengths of a triangle, a and b, the possible values for the third side always fall within this interval: \[\huge (|a-b| \ , \ a+b)\]

OpenStudy (anonymous):

LOL I had a teacher just like that this year, only he was gay so it was a bit interesting as I haven't the foggiest which one I am. Also, @terenzreignz has a very good point.

OpenStudy (anonymous):

Yep lets get on topic

OpenStudy (anonymous):

Also, for your info, I am in fact a guy.

OpenStudy (anonymous):

And agreed.

terenzreignz (terenzreignz):

Don't I just love having good points :D So, you see, @FradyCatt Using your first example, where a and b are both 6, then the possible values for the third side are in this interval... (|6-6| , 6+6)=(0 , 12) So, which values fall within that interval? You be the judge ;)

OpenStudy (anonymous):

I still think my first answer holds true.

hartnn (hartnn):

yes, it does.

terenzreignz (terenzreignz):

LOL that it does :D

OpenStudy (anonymous):

10, 6, 3, 2

terenzreignz (terenzreignz):

And those are your answers. You may thank me later. ;)

OpenStudy (anonymous):

Or me!

hartnn (hartnn):

or me!

hartnn (hartnn):

lol

OpenStudy (anonymous):

Thank you all

OpenStudy (anonymous):

@hartnn , your first answer would have gotten him the problem wrong!

terenzreignz (terenzreignz):

Would it?

OpenStudy (anonymous):

'Twould.

hartnn (hartnn):

on sec, no. :P

OpenStudy (anonymous):

Better to not have to correct it. Less confusion all around.

terenzreignz (terenzreignz):

It was correct o.O Unless I'm missing something.

hartnn (hartnn):

yeah, it was..

hartnn (hartnn):

i got confused when you asked, 'greater than...'

OpenStudy (anonymous):

Yes, you are. If you use less than, it's correct. but if it's equal to, then the whole thing becomes a line.

OpenStudy (anonymous):

I was confused the whole time lol

OpenStudy (anonymous):

God, me too.

hartnn (hartnn):

sorry for confusion guys.

OpenStudy (anonymous):

No problem

OpenStudy (anonymous):

So, I'll attempt some finality. Your answer must satisfy the following equation. \[SideA+SideB > SideC\]

Directrix (directrix):

Triangle Inequality Theorem: One side of a triangle has length less than the sum of the other two.

OpenStudy (anonymous):

Yes, we know.

terenzreignz (terenzreignz):

Finality? Because this interval is awesome, I'm going to write it one more time :D Given the two side lengths a and b, the length of the third side must be in this interval \[\large (|a-b| \ , \ a+b)\]

Directrix (directrix):

Yes, and the third side is greater than the positive difference of the other two sides as well. In this case, (6-6) < 3rd side < (6 + 6) @FradyCatt

OpenStudy (anonymous):

You don't need that long and complicated interval. It just adds confusion.

terenzreignz (terenzreignz):

On the contrary, your criterion was rather insufficient, because the side C could be smaller than the positive difference of the two original sides.

OpenStudy (anonymous):

It could, but if you use common sense and discard 0 or negative answers, it works just fine.

terenzreignz (terenzreignz):

No, I meant, for instance, in a question he/she PM'ed me, given the two lengths 7 and 12 Using the criterion you gave, one of the choices, 3, fits it, but is certainly not a possible length of the third side. It takes more than common sense to see that (methinks), so I think you have to consider the positive difference, and hence the interval.

OpenStudy (anonymous):

He i;m a he and my name is Josh

terenzreignz (terenzreignz):

I'm Terence. Nice to meet you :)

OpenStudy (anonymous):

Nice to meet you too

OpenStudy (anonymous):

My name is Edward. Nice to meet all of you.

OpenStudy (anonymous):

same to you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!