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Mathematics 24 Online
OpenStudy (anonymous):

How do you integrate sinx/ cost?

OpenStudy (anonymous):

can you rewrite the ques?

OpenStudy (anonymous):

Integral sinx divided by cosx ex

OpenStudy (anonymous):

Dx

OpenStudy (anonymous):

\[\int\limits \frac{ \sin x }{ \cos x e ^{x} } dx\]

OpenStudy (anonymous):

can you make a substitution here?

OpenStudy (anonymous):

Just take off the ex that was a typo

OpenStudy (anonymous):

okay in that case just make a substitution let u = cos x

OpenStudy (anonymous):

you know substitution rule right?

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I need step by step Please

OpenStudy (anonymous):

since you're making a u substitution, that means you need to integrate in terms of u and not x basically you need to find dx in terms of du since you have u = cos x we take the derivative du= - sin x dx dx= -du/ sin x substitute that back into your integral then integrate once you've integrated, substitute u back into the equation

OpenStudy (anonymous):

Oh ok.so how does it look like when I substitute it back. Because I did and it doesn't look right

OpenStudy (anonymous):

\[\int\limits_{}^{} \frac{\sin x}{\cos x} dx \] \[u=\cos x\] \[\int\limits_{}^{} \frac{\sin x}{u} dx \] \[du = (- \sin x) dx\] \[-du = \sin x dx\] note that we have sin x dx on the top of hte original integral and that it is equal to - du \[\int\limits_{}^{} \frac{-1}{u} du \] now integrate the substitute u back in

OpenStudy (anonymous):

Thank you so much!

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