Find the domain of the function:
f(x)= sqrt(x+8) / (x-3

Answer: (-inf, -8] U [3, inf)

Is that the right answer folks?

Question

Find the domain of the function:
f(x)= sqrt(x+8) / (x-3

Answer: (-inf, -8] U [3, inf)

Is that the right answer folks?

anonymous · Answer

$$f(x)= \frac{ \sqrt{x+8}\ }{ x-3 }$$

campbell_st · Answer

well what value can't you have in the denominator


or

what value makes

x - 3 = 0....?

this will be the 1st restriction on the domain

campbell_st · Answer

next have a look at the numerator, I'll assume you are working in real numbers.. 

you can't have a negative square root... 

so you need to solve

x + 8>=0

campbell_st · Answer

now you can start to decide what values can be in the domain

anonymous · Answer

still getting -8<=x<3 not sure i follow you campbell

anonymous · Answer

im trying to figure this out!

anonymous · Answer

@campbell_st  so I'm getting a different answer:

$$x \neq3, x \ge-8$$

So my interval notation would be:
[-8,3) U (3,infty)

campbell_st · Answer

thats the correct solution the denominator can be any real value except x = 3

and the numerator needs values greater than or equal to -8

anonymous · Answer

COOL!!! and there is the U (or) sign in the middle...

campbell_st · Answer

well thats set theory notation.... but makes sense,

anonymous · Answer

it says to enter the answer as either interval or union of intervals