Question

If you help me I will become a fan. In serious help.

Answer 1

An octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in cm and the area is 392.4 in2. A second octagon has corresponding side lengths equal to 21.8 in. Find the area of the second octagon. Round to the nearest hundredth.

Answer 2

explain step by step?

Answer 3

You mean a regular octagon, I think.
How many times bigger is the side length of the second octagon?

Answer 4

two times bigger?

Answer 5

This is a ratio type of problem. You have to solve the question based on ratio principles.

Answer 6

There is a easy rule for similar figures and their side lengths, their areas and (when 3d, like cubes) their volumes:

If the sides of figure B are n times the sides of figure A, then

- B's perimeter is n times that of A.
- B's area is n² times that of A
- B's volume is n³ times that of A.

Answer 7

These are the steps I had in mind. Now you must take yours...

Answer 8

huh thats kind of consfusing..lol

Answer 9

Also, you might have to divide the octagon into two trapezoids and one rectangle. That should help you solve common area shapes. Then you would add up the areas of each area shape you calculate. For more procedures, take a look at the attached file.

Answer 10

what is the n?

Answer 11

what s the n?

Answer 12

It is the "enlargement factor". In your problem, the second octagon has lengths of 21.8 in, while the smaller one has 10.9 in.
So the larger one is 2 times bigger, so n=2.

Answer 13

okay thank you!

Answer 14

@Dean.Shyy : that's also what I thought of at first. But after rereading the question, I saw that was too much. It is a similarity question.

Answer 15

YW!