Suppose that for a function f(x) we know that
f(3)=5 and f ' (3)=7
We also 'have that g(x)=x^2*f(x)
Find the equation of the line tangent to g(x) at x=3
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OpenStudy (anonymous):
\[g'(x)=2xf(x)+x^2f'(x)\] by the product rule so
\[g'(3)=2\times 3\times f(3)+3^2f'(3)\]
plug in the numbers and get out your slope
OpenStudy (anonymous):
My calculator keeps giving me error
OpenStudy (anonymous):
this is not a calculator exercise
OpenStudy (anonymous):
\[2\times 2\times5+9\times 7\] is the slope
OpenStudy (anonymous):
6f(3)+9f'(3)
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OpenStudy (anonymous):
83
OpenStudy (anonymous):
i meant
\[2\times 3\times 5+9\times 7\]
OpenStudy (anonymous):
93
OpenStudy (anonymous):
is the slope
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
ok then what
OpenStudy (anonymous):
the point is \((3,3^2\times 5)\)
OpenStudy (anonymous):
better known as \((3,45)\)
last step is point - slope formula
OpenStudy (anonymous):
ok how do you do that
OpenStudy (anonymous):
can someone help me
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OpenStudy (anonymous):
do you know how to find the equation of a line given a point and a slope?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
if the slope is \(m\) and the point is \((x_1,y_1)\) then the equation for the line is
\[y-y_1=m(x-x_1)\]
this is called the point - slope formula
OpenStudy (anonymous):
what are the x and y values if you on;y have (3,45)
OpenStudy (anonymous):
yes, that is all you need, one point \((3,45)\) and the slope \(m=93\)
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OpenStudy (anonymous):
ok so then would it be 45=93-3
OpenStudy (anonymous):
ok lets back up a second
OpenStudy (anonymous):
you are being asked for the equation of a line right?
OpenStudy (anonymous):
usually it would look like \(y=mx+b\)
OpenStudy (anonymous):
yes the tangent line at x=3
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OpenStudy (anonymous):
so your answer needs to look like \(y=mx+b\)
OpenStudy (anonymous):
y=93x+42
OpenStudy (anonymous):
\[y-y_1=m(x-x_1)\] is the point slope formula
replace \(m\) by \(93\), \(x_1\) by \(3\) and \(y_1\) by \(45\)
OpenStudy (anonymous):
you get
\[y-45=93(x-3)\]
OpenStudy (anonymous):
now you can solve this for \(y\) to make it look like \(y=mx+b\)
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OpenStudy (anonymous):
so then are the y and x 0
OpenStudy (anonymous):
oh ok just a minute
OpenStudy (anonymous):
y=138(x-3)
OpenStudy (anonymous):
\[y = 93 x-234\]
OpenStudy (anonymous):
oh ok I added the wrong thing together
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OpenStudy (anonymous):
multiply out using the distributive law, then add 45
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so then the y=93x-234 is the equation correct
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
ok thanks
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