a local maximum value of the function y= e^x / x is.......
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OpenStudy (anonymous):
can you find the critical numbers?
OpenStudy (anonymous):
i just have the multiple responses to it. a) 1/e b) 1 c) -1 d) e e) 0
OpenStudy (anonymous):
we cant give answers but we can show how to get it... sorry...
OpenStudy (anonymous):
oh okay sorry i am new to this
OpenStudy (anonymous):
i got 1
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OpenStudy (anonymous):
the best way to do this without knowing calculus is by graphing it....
OpenStudy (anonymous):
o so its -1
OpenStudy (anonymous):
are you sure the question asks for a local maximum? or is it local minimum?
OpenStudy (anonymous):
oh yeah local minimum
my bad
OpenStudy (anonymous):
so just read what your calculator has as the local min...
if you don't have a graphing calculator, use this free online one:
https://www.desmos.com/calculator
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OpenStudy (anonymous):
well i graphed it but what point am isupposed to look at
OpenStudy (anonymous):
you're supposed to look at where on the graph is a local minimum...
OpenStudy (anonymous):
i got -1
OpenStudy (anonymous):
here's a screenshot....
OpenStudy (anonymous):
yeah i got that
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OpenStudy (anonymous):
x=-1 is not where the local minimum occurs...
OpenStudy (anonymous):
0
OpenStudy (anonymous):
what's the definition of a local minimum?
OpenStudy (anonymous):
lowest value on a graph?
OpenStudy (anonymous):
so what's the value at x=0 ?
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OpenStudy (anonymous):
something really small n negative
OpenStudy (anonymous):
>-10
OpenStudy (anonymous):
i mean less <-10***
OpenStudy (anonymous):
can you be more specific? -100? -1000? -100009? what's the value at x=0?
OpenStudy (anonymous):
idk its never ending
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OpenStudy (anonymous):
-100000000000
OpenStudy (anonymous):
right... therefore, at x=0, you DO NOT have a local minimum...
OpenStudy (anonymous):
so this whole function doesn't have one?
OpenStudy (anonymous):
yes it does...
i just think you don't have the proper definition of what a "local minimum" is...
OpenStudy (anonymous):
a local minimum is a point on the graph that is the lowest value when you consider other points very close to it....
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OpenStudy (anonymous):
so at x=1
theres a local minimum cuz of it decreasing to the lowest point
OpenStudy (anonymous):
yes..... at x=1, the value is the lowest when you consider it's neighboring points.
OpenStudy (anonymous):
yayyyy thank you
OpenStudy (anonymous):
yw...:)
OpenStudy (anonymous):
but i think your instructor wanted you to do this using calculus right?
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OpenStudy (anonymous):
yeah probably
OpenStudy (anonymous):
lol...
OpenStudy (anonymous):
how would u do it with calc
OpenStudy (anonymous):
\(\large y=\frac{e^{x}}{x} \)
you'll need to first find the critical number(s) by taking the derivative dy/dx....
did you want to do it that way?
OpenStudy (anonymous):
lnx e^x?
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OpenStudy (anonymous):
no wait its ok i don't need to do it that way just asked someone