I shouldn't be struggling with this like I am need some help

Question

anonymous · Answer

Consider the function 
$$f(x)=\frac{ 6 }{ x^3 }-\frac{ 4 }{ x^5 }$$
Let F(x) be the antiderivative of f(x) with F(1) = 0.
Then F(x) =

unklerhaukus · Answer

does it help to rewrite like this  
$$f(x)=6x^{-3 }-4 x^{-5 }$$

anonymous · Answer

did that and have an anti-derivative of 
-3x^-2+x^-4 that derives back into original function

anonymous · Answer

$$-3x ^{-2}+x ^{-4}$$

unklerhaukus · Answer

dont forget to +c

anonymous · Answer

grrr I hate +C

anonymous · Answer

that should help
I need to get to bed I'll deal with it again in the morning thanks

anonymous · Answer

You want to use: $$F'(x)=f(x) \implies 
\int_1^x f(x)dx  = F(x) - F(1) \implies F(x) = \int_1^x f(x)dx +F(1)
$$Since after all, they gave you $F(1)=0$.

anonymous · Answer

yeah I was missing the +C and I think that was my problem, haven't tried it yet but headed to bed

unklerhaukus · Answer

$$F(x)=-3(x) ^{-2}+(x) ^{-4}+c$$
$$F(1)=-3(1) ^{-2}+(x)^{-4}+c=0$$
solve for $c$ and finally put this into back into $F(x)$

anonymous · Answer

I can only assume this is calculus from the way it makes my brain hurt :c 
Good luck you poor soul