A person on a bridge 80 m above a stream sees a bottle drifting along at a constant speed. He drops a stone when the bottle has 7.2 m more to travel before passing under the bridge. The stone hits the water 2.32 m in front of the bottle. Calculate the speed of the drifting bottle.
I would find out how long it took the stone to go 80m first
Then use the time taken for the stone to travel 80m and divide it into the total distance traveled by the bottle during the stone's free fall 7.2-2.32m. That should get you to the velocity (m/s) of the bottle :D
Solving for T in the Kinematic equation, I found T=2.02s for the stone to hit the stream. Then did 4.88m/2.02s to get V of the bottle. I got 2.42m/s as the velocity of the bottle in the stream
do you understand all of this? or do you need further explanation?
Im pretty sure I got it... Thanks!
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