Check my answer? (derivatives)
\[y=\frac{ x+1 }{ x ^{3} +x-2}\]
i got \[\frac{ -5x ^{3} -3}{(x ^{3}+x-2)^{2} }\]
thats a 5x^3 i couldnt figure out how to make the test larger :(
x^3 as well in the equation and my answer
I know wolfram can answer it but they have it in a different form than how i solve it
or better still http://www.wolframalpha.com/input/?i=%28x%2B1+%29%2F%28+x+^3+%2Bx-2%29
if you got something other than wolf's answer, it is a mistake
Actually, no. there is several ways to write it.
can you show how you got that numerator ? we'll help you spot the error.
not really
you can distribute the minus sign, but not much else
I believe it is correct? looking at wolfram they just didnt foil the negative
apparantely, there is some mistake somewhere in your work...
I dont think there is...
I got -(2x^3+3x^2+3) in the numerator.
can you please post how you got it ? and let us verify ?
In the denominator I just got the denominator of the original fraction squared.
that was what i got lol
\[gf'-f'g\] is the numerator with \(f(x)=x+1,f'(x)=1,g(x)=x^3+x-3,g'(x)=3x^2+1\)
-5x^3-3/(x^3+x-2)^2
Wolfram didnt foil the negative.
Thats why its different
derivative of top times the bottom is just x^3+x-2 derivative of the bottom times the top is (3x^2+1)(x+1)
...
\[(x^3+x-3)\times 1-(3x^2+1)(x+1)\]
that is the algebra you need. not exactly sure what "foil the negative" means
lol.
I am not processing math curently so I am typing all this long hand as opposed too using the equation editor.
its alright, i got it.
I am sure he meant distribute.
I did. calmat. :)
got my algebra terms mixed in somehow
LOL!
somewhere on your computer you have that saved
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