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Mathematics 28 Online
OpenStudy (anonymous):

Check my answer? (derivatives)

OpenStudy (anonymous):

\[y=\frac{ x+1 }{ x ^{3} +x-2}\]

OpenStudy (anonymous):

i got \[\frac{ -5x ^{3} -3}{(x ^{3}+x-2)^{2} }\]

OpenStudy (anonymous):

ciy http://www.wolframalpha.com/input/?i=y%3D \frac{+x%2B1+}{+x+^{3}+%2Bx-2}

OpenStudy (anonymous):

thats a 5x^3 i couldnt figure out how to make the test larger :(

OpenStudy (anonymous):

x^3 as well in the equation and my answer

OpenStudy (anonymous):

I know wolfram can answer it but they have it in a different form than how i solve it

OpenStudy (anonymous):

or better still http://www.wolframalpha.com/input/?i=%28x%2B1+%29%2F%28+x+^3+%2Bx-2%29

OpenStudy (anonymous):

if you got something other than wolf's answer, it is a mistake

OpenStudy (anonymous):

Actually, no. there is several ways to write it.

hartnn (hartnn):

can you show how you got that numerator ? we'll help you spot the error.

OpenStudy (anonymous):

not really

OpenStudy (anonymous):

you can distribute the minus sign, but not much else

OpenStudy (anonymous):

I believe it is correct? looking at wolfram they just didnt foil the negative

hartnn (hartnn):

apparantely, there is some mistake somewhere in your work...

OpenStudy (anonymous):

I dont think there is...

OpenStudy (anonymous):

I got -(2x^3+3x^2+3) in the numerator.

hartnn (hartnn):

can you please post how you got it ? and let us verify ?

OpenStudy (anonymous):

In the denominator I just got the denominator of the original fraction squared.

OpenStudy (anonymous):

that was what i got lol

OpenStudy (anonymous):

\[gf'-f'g\] is the numerator with \(f(x)=x+1,f'(x)=1,g(x)=x^3+x-3,g'(x)=3x^2+1\)

OpenStudy (anonymous):

-5x^3-3/(x^3+x-2)^2

OpenStudy (anonymous):

Wolfram didnt foil the negative.

OpenStudy (anonymous):

Thats why its different

OpenStudy (anonymous):

derivative of top times the bottom is just x^3+x-2 derivative of the bottom times the top is (3x^2+1)(x+1)

OpenStudy (anonymous):

...

OpenStudy (anonymous):

\[(x^3+x-3)\times 1-(3x^2+1)(x+1)\]

OpenStudy (anonymous):

that is the algebra you need. not exactly sure what "foil the negative" means

OpenStudy (anonymous):

lol.

OpenStudy (anonymous):

I am not processing math curently so I am typing all this long hand as opposed too using the equation editor.

OpenStudy (anonymous):

its alright, i got it.

OpenStudy (anonymous):

I am sure he meant distribute.

OpenStudy (anonymous):

I did. calmat. :)

OpenStudy (anonymous):

OpenStudy (anonymous):

got my algebra terms mixed in somehow

OpenStudy (anonymous):

LOL!

OpenStudy (anonymous):

somewhere on your computer you have that saved

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