Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

a plane takes off heading west at a ground velocityof 500kph and climbing at an angle of 8 degrees. A 15kph wind is blowing from the north. Determine the resultant air and ground velocities (sketch and label a diagram)

OpenStudy (zehanz):

Here is a start:

OpenStudy (anonymous):

ok but can u draw a simple diagram please

OpenStudy (zehanz):

It is a 3d-situation, so a diagram is not that easy. I've tried to make simplified diagrams (top view and side view). The length of the green vector (495.36 km/h) is the ground speed (used Pythagorean Theorem). The length of the red vector (500.22 km/h) is the airspeed (imo).

OpenStudy (zehanz):

Calculating angles could also easily done with the diagrams...

OpenStudy (anonymous):

what i did was use the cosine law to find the resultant: r^2=(15)^2+(500)^2-2*15*500cos 88

OpenStudy (anonymous):

is this right?

OpenStudy (zehanz):

No, I don't think so. Because the wind is perpendicular to the direction the plane is going, you must use the Pythagorean Theorem to find the resultant. See my drawings. Furthermore, while the wind adds to the speed, your calculation leads to a lower speed. (about 485 km/h).

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!