The equation shows one mole of ethanol fuel being burned in oxygen. Convert the energy released into its equivalent mass. C2 H5 OH (l) + 3 O2 (g) --> 2 CO2 (g) + 3 H2O (l) deltaH = -1418 kJ/mol I am not sure where to begin with this one.
E=mc^2 ?
isnt that the only energy-mass relation?
but first, convert molar mass to kg and then perform the steps
Should I insert -1.418 * 10^6 for E?
no. use gram eq. wt. of ethanol to convert deltaH (in per mole) to per kG
could you show me perhaps?
1mole C2H5OH = 2(12)+5(1)+16+1 = 46 deltaH = -1418/46 10^6 J/kg \[m = E/c^2\\ m=\frac{-1416\times10^6}{46}\times{1\over (3\times10^8)^2} \]
but the question asks for energy released by 1 mole . so, \[m=\frac{-1416\times10^3}{(3\times10^8)^2} \]
-ve sign can be ignored. indicates loss of mass
Join our real-time social learning platform and learn together with your friends!