Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

Prove: cotx+tanx=cotx * sec^2x

hartnn (hartnn):

write sec^2x = .... ?

OpenStudy (anonymous):

1/cos^2x

hartnn (hartnn):

1+ tan^2 x ?

OpenStudy (anonymous):

sec^2x

hartnn (hartnn):

then you can use directly here, tan x cot x =1

OpenStudy (klimenkov):

All you need to know is the definition of \(\tan x, \cot x, \sec x\) and how to work with fractions.

hartnn (hartnn):

yes, so i said to replace sec^2 x by 1+tan^2x

hartnn (hartnn):

can be solved without involving fractions ... :)

hartnn (hartnn):

@koli123able did you try ?

OpenStudy (anonymous):

which side to choose?

hartnn (hartnn):

right ...?

hartnn (hartnn):

cotx * sec^2x=cotx * (1+tan^2 x) =..... ?

OpenStudy (anonymous):

cotx+ cotx tan^2x

OpenStudy (anonymous):

cotx tanx becomes 1

hartnn (hartnn):

cotx+ cotx tan^2x = cot x + tan x (cot x tan x)

OpenStudy (anonymous):

is that an identity cot x tanx =1 ??

hartnn (hartnn):

absolutely. tan x = 1/cot x so, tan x cot x =1

OpenStudy (anonymous):

cosx/sinx =sinx/cosx

OpenStudy (anonymous):

cos^2x + sin^2x / cosx sinx

OpenStudy (anonymous):

1/cosxsinx

OpenStudy (anonymous):

cscx+secx

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!