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Prove: cotx+tanx=cotx * sec^2x
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write sec^2x = .... ?
1/cos^2x
1+ tan^2 x ?
sec^2x
then you can use directly here, tan x cot x =1
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All you need to know is the definition of \(\tan x, \cot x, \sec x\) and how to work with fractions.
yes, so i said to replace sec^2 x by 1+tan^2x
can be solved without involving fractions ... :)
@koli123able did you try ?
which side to choose?
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right ...?
cotx * sec^2x=cotx * (1+tan^2 x) =..... ?
cotx+ cotx tan^2x
cotx tanx becomes 1
cotx+ cotx tan^2x = cot x + tan x (cot x tan x)
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is that an identity cot x tanx =1 ??
absolutely. tan x = 1/cot x so, tan x cot x =1
cosx/sinx =sinx/cosx
cos^2x + sin^2x / cosx sinx
1/cosxsinx
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cscx+secx
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