Question

Factor completely: 2x3 + 14x2 + 4x + 28

Answer 1

I am stuck between two answers

Answer 2

2(x3 + 7x2 + 2x + 14)

(2x + 14)(x2 + 2)

Answer 3

2(x+7)(x^2+2)

Answer 4

i think?

Answer 5

Split up in two times two terms:

(2x³ + 14x²) + (4x + 28)=2x²(x+7) + 4(x+7)

Answer 6

Now you can see that there is a "new" common factor: x+7. So it can be factored out:

(2x²+4)(x+7)

Answer 7

I agree with Pooja....2(x + 7)(x^2 + 2)

Answer 8

so it would be the second choice?

Answer 9

or would it be 2[(x + 7)(x2 + 2)]

Answer 10

Of course, now the hard work has been doe, it's time to clean up:

(2x²+4)(x+7)=2(x²+2)(x+7)

Answer 11

thank you!

Answer 12

So there really is no difference between @pooja195's answer and mine...

Answer 13

YW!

Answer 14

:)

Answer 15

What I don't get is this: you're supposed to factor *completely*, but you can choose between:

2(x3 + 7x2 + 2x + 14)
and
(2x + 14)(x2 + 2)

both of which are not factored completely...