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OpenStudy (anonymous):
Compute the derivative of cos(sqrt(x)) , with respect to x from first principle.
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OpenStudy (anonymous):
@experimentX @Mashy
OpenStudy (anonymous):
it would be \[-1/2 \sin x\]
OpenStudy (anonymous):
I am not 100 percent sure
OpenStudy (anonymous):
isnt the derivative of cos(sqrt(x)) = -sin(sqrt(x))/2sqrt(x)
OpenStudy (anonymous):
yea that seems right
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OpenStudy (johnweldon1993):
i believe so @ton12
OpenStudy (anonymous):
y u asking if you know lol
OpenStudy (anonymous):
But Hw do u Figure out with 1st principle it is getting werid with that
OpenStudy (anonymous):
\[-1/2 x ^{-1/2}\sin \sqrt{x}\]
OpenStudy (anonymous):
i want to figure out it from 1st principle @aajugdar
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OpenStudy (anonymous):
uh well
differentiate root x
then differentiate sin root x
then multiply
OpenStudy (anonymous):
chain rule
OpenStudy (anonymous):
What is first principle?
OpenStudy (anonymous):
lim h--->0 ( f(x+h) - f(x) ) / h
OpenStudy (anonymous):
oh lol
okay
lets see
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OpenStudy (anonymous):
Lt h->0 [cos (√(x+h) - cos √x) ]/h = - 1/h *2 * sin (√x+h +√x) /2 sin (√(x+h) -√x)/2
= - (2sin √x) lt h-->0 1/h *sin (h/2 ((√x+h +√x) ) = - (2sin √x) * sin (h/2 ((√x+h +√x) )
----------------------------------------…
2 ((√x+h +√x) * (h/2 ((√x+h +√x) )
- (2sin √x) * 1/(2* 2√x) * 1 = -1/2√x * sin √x
OpenStudy (anonymous):
try to get it
lol
OpenStudy (anonymous):
check on the site
you will understand
OpenStudy (anonymous):
thxx buddy
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OpenStudy (anonymous):
you are welcome :)
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