Question

i am doing polynomial long division and trying to figure out how to solve this.(2b^4+7b^2+5)/(b^2+3) HELP PLEASE

Answer 1

set it up like that

Answer 2

now...how many times does b^2 go into 2b^4?

Answer 3

2b^2 right

Answer 4

correct :) so now write that on top of that big line.....and now.....

what is b^2 times 2b^2...yes 2b^4
what is 3 times 2b^2?

Answer 5

6b^2?

Answer 6

correct again...so this is what it looks like with that....this is what we have left

Answer 7

nowwwww how many times does b^2 go into b^2? dont overthink it :D lol

Answer 8

so it would be 2b^2+1 right

Answer 9

no just b^2....remember the 2b^2 part is gone now

Answer 10

you ask yourself...how many times does b^2 from your (b^2 +3) go into b^2 from the remaining (b^2 +5)

so now how many times does b^2 go into b^2?

Answer 11

oh wait...you mean on top....oh...yes lol 2b^4 + 1 on top

Answer 12

what i'm talking about is what is on top of the equation the answer to your question is 1

Answer 13

BUT.....whe you subtract what you have you get

Answer 14

0

Answer 15

you have a remainder of 2 right?

Answer 16

oh subtract the 5 and the 3 ok

Answer 17

yah a remainder of 2

Answer 18

okay...what you do with that remainder...is you put it over your original function that you are dividing with

your final answer will be

the

2x^2 + 1

and then after that you would put 2/(x^2 + 3)

so your final answer is

\[2b^2 + 1 + 2/(b^2 + 3)\]

Answer 19

Ok thank you I really needed the help

Answer 20

\[2b^2 + 1 + \frac{ 2 }{ b^2 + 3 }\]

looks more clear this way lol

Answer 21

thanks again

Answer 22

anytime :)