Question

Please help me with this integration!

Answer 1

\[\int\limits 1/(x^2-9)^(3/2)\]

Answer 2

Thats supposed to be to the power of 3/2

Answer 3

a substitution of x= 9 secy might help maybe ?

Answer 4

I meant x= 3secy

Answer 5

Umm okay could you explain it a little more? Im lost on the whole integration thing :P

Answer 6

\[\int\limits \frac{ 1 }{\sqrt(x^2 - 9)^3 } dx \]
\[x = 3\sec(\Theta)\]
\[\int\limits \frac{ 2tan(\theta)sec^2(\theta) }{\sqrt(9sec^2(\theta) - 9)^3 } d\theta \]
\[\int\limits \frac{ 2tan(\theta)sec^2(\theta) }{\sqrt(9(sec^2(\theta) - 1))^3 } d\theta \]
the identity \[sec^2(\theta) - 1 = tan^2\theta\] will help here
\[\int\limits \frac{ 2tan(\theta)sec^2(\theta) }{\sqrt(9tan^2(\theta))^3 } d\theta \]
\[\int\limits \frac{ 2tan(\theta)sec^2(\theta) }{3tan(\theta)^3 } d\theta \]
do you need help from there?

Answer 7

Yes please.....Im really lost in this whole thing...

Answer 8

Ive been trying to get myself back into the whole integrating thing....But its be coming rather difficult without a actual teacher -_-

Answer 9

first of all you would have to know that to integrate power functions, you would have to add 1 to the power and divide the base by the result....