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Mathematics 22 Online
OpenStudy (anonymous):

prove that ku=[ku1,ku2,ku3] for any vector u=[u1,u2,u3] and any scaler KER

OpenStudy (anonymous):

As far as I can tell, it looks like you're supposed to prove a given set of vectors is closed under scalar multiplication. The problem is that it's impossible to say, since we don't know anything about \(u\).

OpenStudy (anonymous):

thats all Im given.

OpenStudy (anonymous):

After looking your question over, it looks like the vector \(u\in\mathbb{R}^3\), and hence \(u=(u_1,u_2,u_3).\) So all you have to show is that \[ku=(ku_1,ku_2,ku_3),\;\forall k\in\mathbb{R}.\] If you understand the notion of why a vector in \(\mathbb{R}^3\) has three components, it should be pretty easy to understand that multiplying a vector by a scalar is the same as multiplying its components by a scalar.

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