prove that ku=[ku1,ku2,ku3] for any vector
u=[u1,u2,u3] and any scaler KER

Question

prove that ku=[ku1,ku2,ku3] for any vector 
u=[u1,u2,u3] and any scaler KER

anonymous · Answer

As far as I can tell, it looks like you're supposed to prove a given set of vectors is closed under scalar multiplication. The problem is that it's impossible to say, since we don't know anything about $u$.

anonymous · Answer

thats all Im given.

anonymous · Answer

After looking your question over, it looks like the vector $u\in\mathbb{R}^3$, and hence $u=(u_1,u_2,u_3).$

So all you have to show is that
$$ku=(ku_1,ku_2,ku_3),\;\forall k\in\mathbb{R}.$$
If you understand the notion of why a vector in $\mathbb{R}^3$ has three components, it should be pretty easy to understand that multiplying a vector by a scalar is the same as multiplying its components by a scalar.