calculus problem
|dw:1363576146820:dw| the disc has an infinitesimal volume of dV=area of disc * the infinitesimal height=2*pi*r^2 * dy total volume is sum (integral) of all such tiny volumes from y=0 to y=9 \[V\pi\int_{y=0}^9r^2dy\]
oooooo yes but then idk how to go from there cuz the bakc of the book says a. 40.5pi or 127 and i got 243..
so, put them there... \[ V=\pi\int_0^9(\sqrt{9-y})^2dy=\pi\int_0^9(9-y)dy=\pi\left[9y-{y^2\over2}\right]_0^9\\ V=\pi(81-81/2)={81\pi\over2} \]
what about b.
use simpson's, trapeziodal or Reimann sums or other numerical methods to approximate the value..
"Numerical"....
they should be very close.. Analytical is the most accurate one and numerical ones based on your "h" value (interval size).. the more number, more work to do , more accurate
o ok imma try trapezoidal
whats n again
just choose one.. try 20 pieces?
can u show me ur work? i just got 60.5 -_-
no. put yours.. that way you "learn" :)
btw, is that close to 40.5*pi?
not really cuz im supposed to get arund 30 according to my friend
nope... 40.5*3.14 is a little more than 121
or 127 like you said in your previous reply.
i mean for b.. but ok lol
both are the same volume! gotta be equal
oh ok thank you 1: D
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