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Mathematics 24 Online
OpenStudy (anonymous):

find a parameterization for the curve y^2 = x^3 from (4,8) to (1,1)

OpenStudy (anonymous):

If you let \(x(t)=t\) then you can solve for \(y(t)\) using \([y(t)]^2=[x(t)]^3=t^3\)

OpenStudy (anonymous):

Then just find values of \(t\) such that \(x(t)=1,\;y(t) = 1\) and \(x(t)=4,\;y(t) = 8\)

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