Question

Need help, see attachments

Answer 1

10

Answer 2

10

Answer 3

is it potssible?

Answer 4

(a) The mean is
\[205\times 0.15=?\]
The standard deviation is
\[\sqrt{(205\times 0.15\times 0.85)}\]

Answer 5

i got 5.1125 something

Answer 6

I need help with last one

Answer 7

can you help on last one , cuz I really don't get t

Answer 8

(c) This part can be solved by using the Normal Approximation of the Binomial Distribution. As found in part (a) the mean = 31 and the standard deviation = 5.112.
There are 27 seats available for left handed people so we need to find the probability that the number of left handed people is equal to, or fewer than 27.
In this case the z-score is calculated as follows:
\[z=\frac{27-31+0.5}{5.112}=-0.6847\]
Note: The term 0.5 in this calculation is a correction caused by the change from a discrete to a continuous distribution.
A standard normal probability table gives a cumulative probability of 0.247

Answer 9

i have that formula

Answer 10

i need to use that for last one

Answer 11

p hat is equal to = x/n

Answer 12

The question you have posted does not involve sampling. Therefore the formula you have posted does not apply.