Boolean Algebra, Convert X = (A + B)(A + B + C) to standard form.
what you need help on
The steps for converting it, I know the answer but i dont know the steps to it
Whenever you want to convert standard form ax + by = c to slope-intercept form, y = mx + b, what you essentially want is to solve for y. In your example: 2x + 5y = 10 Begin by subtracting 2x from both sides of the equation. 2x-2x + 5y = 10 - 2x 5y = 10-2x Now, divide by the coefficient of y, in this case, 5. 5y/5 = 10/5 -2x/5 y = 2 - (2/5)x To put this in proper form, write the terms in descending order, x term before constant: y = - (2/5)x + 2
the answer is y = - (2/5)x + 2
Dude that's Boolean algebra it is based on a number system with base "2" , it is totally different from normal algebra.. :P
yea lol
give me best response
oki I will once I receive it
what is standard form, any example ?
all the domains have the same variables
so, you should have mentioned that you need POS standard form.... because POS and SOP forms are both standard and they are different.
in this case you add a number that is equal to 0 in boolean algebra just to play with some rules but its messed up
X = (A + B)(A + B + C) is already POS
its POS but not standard POS, because standard POS contains all the variables in each term.
so, you need to add the term C , but you can't just add ti so, we use the fact that CC'=0 and since adding 0 doesnot change anything, we can add it without altering the given equation
i think rule 12 there would have stated this more clearly...
then you just apply this standard boolean identity \(\large (x+yz)=(x+y)(x+z)\)
ok and??
so, (A'+B') = (A'+B'+CC') =... ?
treat x=A'+B' y=C z=C'
You gave me a good clue thanks!
welcome ^_^
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