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Mathematics 11 Online
OpenStudy (christos):

Boolean Algebra, Convert X = (A + B)(A + B + C) to standard form.

OpenStudy (anonymous):

what you need help on

OpenStudy (christos):

The steps for converting it, I know the answer but i dont know the steps to it

OpenStudy (anonymous):

Whenever you want to convert standard form ax + by = c to slope-intercept form, y = mx + b, what you essentially want is to solve for y. In your example: 2x + 5y = 10 Begin by subtracting 2x from both sides of the equation. 2x-2x + 5y = 10 - 2x 5y = 10-2x Now, divide by the coefficient of y, in this case, 5. 5y/5 = 10/5 -2x/5 y = 2 - (2/5)x To put this in proper form, write the terms in descending order, x term before constant: y = - (2/5)x + 2

OpenStudy (anonymous):

the answer is y = - (2/5)x + 2

OpenStudy (christos):

Dude that's Boolean algebra it is based on a number system with base "2" , it is totally different from normal algebra.. :P

OpenStudy (anonymous):

yea lol

OpenStudy (anonymous):

give me best response

OpenStudy (christos):

oki I will once I receive it

hartnn (hartnn):

what is standard form, any example ?

OpenStudy (christos):

http://screencast.com/t/dh8G5J1jMs1C

OpenStudy (christos):

all the domains have the same variables

hartnn (hartnn):

so, you should have mentioned that you need POS standard form.... because POS and SOP forms are both standard and they are different.

OpenStudy (christos):

in this case you add a number that is equal to 0 in boolean algebra just to play with some rules but its messed up

OpenStudy (christos):

X = (A + B)(A + B + C) is already POS

hartnn (hartnn):

its POS but not standard POS, because standard POS contains all the variables in each term.

hartnn (hartnn):

so, you need to add the term C , but you can't just add ti so, we use the fact that CC'=0 and since adding 0 doesnot change anything, we can add it without altering the given equation

hartnn (hartnn):

i think rule 12 there would have stated this more clearly...

hartnn (hartnn):

then you just apply this standard boolean identity \(\large (x+yz)=(x+y)(x+z)\)

OpenStudy (christos):

ok and??

hartnn (hartnn):

so, (A'+B') = (A'+B'+CC') =... ?

hartnn (hartnn):

treat x=A'+B' y=C z=C'

OpenStudy (christos):

You gave me a good clue thanks!

hartnn (hartnn):

welcome ^_^

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