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Mathematics 13 Online
OpenStudy (anonymous):

You have a frame that holds three pictures. You pulled out your favorite five photos. How many sets of three are there? Make a list of all the possible combinations using the numbers 1 - 5 to represent the photos.

OpenStudy (ash2326):

You have 5 photos, you need to find the no, of sets of 3 you can make from 5 pics. It's a problem of combination. Do you understand the problem? @girlpower12345678910

OpenStudy (anonymous):

You have 5 photos, and 1 picture frame that holds 3. Now look at this. If you have 2 picture frames it would be 6, right? All I know. xp

OpenStudy (anonymous):

Thanks guys! Ya'll were a HUGE help!

jimthompson5910 (jim_thompson5910):

I'm sure you figured it out by now, but there are 5 C 3 = (5!)/(3!(5-3)!) = 10 different ways to do this and the 10 ways are listed below 123 124 125 134 135 145 234 235 245 345 Keep in mind that order does NOT matter (so something like 135 is the same as 315)

OpenStudy (anonymous):

Thank you so much jim! Such a huge help

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

I added you as a fan

OpenStudy (anonymous):

Add me

jimthompson5910 (jim_thompson5910):

thanks, and random side note: you sent me a message but it says "user doesn't accept messages" lol

jimthompson5910 (jim_thompson5910):

so just letting you know

OpenStudy (anonymous):

Ok i cant or you cant

jimthompson5910 (jim_thompson5910):

i tried sending you a message back and it told me that

OpenStudy (anonymous):

OH!

jimthompson5910 (jim_thompson5910):

so i think you're not allowed to receive messages? lol

jimthompson5910 (jim_thompson5910):

its ok, just an odd glitch i guess

OpenStudy (anonymous):

It's because I havent looked at the verification link yet

jimthompson5910 (jim_thompson5910):

i gotcha

OpenStudy (anonymous):

what did you say

OpenStudy (anonymous):

in the text you tried sending me

jimthompson5910 (jim_thompson5910):

oh i didn't say anything since it told me right away

OpenStudy (anonymous):

GTG BYE

jimthompson5910 (jim_thompson5910):

but i was just gonna say back "sure thing"

OpenStudy (anonymous):

OK BYE

jimthompson5910 (jim_thompson5910):

alright cya later

OpenStudy (anonymous):

bye

OpenStudy (anonymous):

does anyone know

OpenStudy (anonymous):

agmac???

OpenStudy (anonymous):

yaaaaaaa

OpenStudy (anonymous):

Jim helped me alot

OpenStudy (anonymous):

Wish he was online

jimthompson5910 (jim_thompson5910):

sorry i lost connection, but what is your question?

OpenStudy (anonymous):

OMG! hi

jimthompson5910 (jim_thompson5910):

lol hi, hopefully it's all fixed

jimthompson5910 (jim_thompson5910):

had to reset everything, but it's working (for now...)

OpenStudy (anonymous):

it is you helped SO MUCH

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

here is a question

jimthompson5910 (jim_thompson5910):

glad I did, did you have another question?

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

You roll a number cube. Event A: roll a number less than 3 Event B: roll an odd number Are the events disjointed or overlapping? I think its overlapping because 1 is an odd number. Just clarifying

jimthompson5910 (jim_thompson5910):

Well think of it in terms of venn diagrams (that's how I do it)

OpenStudy (anonymous):

Oh thx i was just making sure ONE MORE BTW

jimthompson5910 (jim_thompson5910):

|dw:1363730840743:dw|

jimthompson5910 (jim_thompson5910):

notice how the number 1 is in BOTH sets

jimthompson5910 (jim_thompson5910):

So there is overlap

jimthompson5910 (jim_thompson5910):

so yeah you got it correct, nice work

OpenStudy (anonymous):

oh my thanks

OpenStudy (anonymous):

can I ask you one more

OpenStudy (anonymous):

MATH WIZARD

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

kk thanks

OpenStudy (anonymous):

hold on it will take a moment

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

You randomly draw a marble from a bag. You then put it back before drawing a second marble. These events are --------- events. independent or dependent

OpenStudy (anonymous):

???? I know I'm dumb just need help though

jimthompson5910 (jim_thompson5910):

you're not dumb, so cut that out

OpenStudy (anonymous):

k k

OpenStudy (anonymous):

thx???

OpenStudy (anonymous):

I guess but answer plz

jimthompson5910 (jim_thompson5910):

they are independent because neither event affects the other

jimthompson5910 (jim_thompson5910):

the first draw doesn't affect the probability of the second draw (or vice versa)

OpenStudy (anonymous):

RIGHT RIGHT RIGHT! Just forgot the definition of independent

jimthompson5910 (jim_thompson5910):

that's ok

OpenStudy (anonymous):

How long are you going to be on

jimthompson5910 (jim_thompson5910):

not sure, how much more do you have?

OpenStudy (anonymous):

all day hon I mean really nice person that cares about other people including me ha lmbo

OpenStudy (anonymous):

There are eight sprinters competing for first, second, and third place ribbons. How many different ways can the ribbons be awarded? 1,680 336 24 8

OpenStudy (anonymous):

Hello? Jim?

jimthompson5910 (jim_thompson5910):

you have 8 choices for the first slot (first place), 7 choices for the second, and 6 choices for the third so you multiply that out to get your answer

jimthompson5910 (jim_thompson5910):

what do you get when you do

OpenStudy (anonymous):

ok thx you get 336?

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

ty so much jim

OpenStudy (anonymous):

Twenty-four girls are trying out for 12 spots on the cheerleading team. If you wanted to determine how many different groups of 12 girls can be created, would you use a permutation or a combination?

OpenStudy (anonymous):

Since you said you don't know how long you would be on.... thought you could help me with a few more?

jimthompson5910 (jim_thompson5910):

The key word is "group", which implies that order does NOT matter

jimthompson5910 (jim_thompson5910):

So you would use a _____

OpenStudy (anonymous):

combination

OpenStudy (anonymous):

This is fun!

OpenStudy (anonymous):

Match the word with its definition. 1. theoretical probability 2. independent events 3. permutation 4. overlapping events 5. dependent events 6. disjointed events 7. combination 8. experimental probability the ratio of favorable outcomes to total possible outcomes events with at least one outcome in common an arrangement of objects where order is not important compound events that are affected by prior events outcomes events with no outcomes in common an arrangement of objects where order is important compound events that are not affected by other's outcomes the ratio of the number of successes to the number of trials

jimthompson5910 (jim_thompson5910):

lol glad you're having fun

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

Match the word with its definition. 1. theoretical probability 2. independent events 3. permutation 4. overlapping events 5. dependent events 6. disjointed events 7. combination 8. experimental probability the ratio of favorable outcomes to total possible outcomes events with at least one outcome in common an arrangement of objects where order is not important compound events that are affected by prior events outcomes events with no outcomes in common an arrangement of objects where order is important compound events that are not affected by other's outcomes the ratio of the number of successes to the number of trials

jimthompson5910 (jim_thompson5910):

what did you get for this one?

OpenStudy (anonymous):

this crazy huh

OpenStudy (anonymous):

you put the numbers beside the one it matches

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