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If possible, solve each equation or inequality. 1.) lxl= -2 2.) l x+9 l >11 3.) x^2 - 2= 14 4.) (x-7)^2 = 169 5.) x^2-2=14 6.) x^2= -2.56
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First one is not solvable, as the modulus of x is always positive. Or you can square both sides of it to get \[x^2 + 18x + 81 < 121\]\[x^2 + 18x -40 <0\]\[(x+20)(x-2)<0\] Now you need to envisage this on a graph,|dw:1363717240758:dw| so the shaded region, is the bit that is less than 0 (as the equation requires. So your solution here is \[-20<x<2\]
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