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Approximate the sum of the series correct to four decimal places. sum from n=1 to infinity of ((-1)^(n+1))/(n^6)
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Would it help if I put it in equation form?
no no that doesn't help ... use approximation for alternating series.
how would I apply it?
find the term that starts from 5th decimal places ... and add up to that term only.
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okay so you would do the sum from n=1 to 5 of (-1)^(n+1)/(n^6)?
No no ... http://upload.wikimedia.org/math/1/9/5/1958a6b59874cfdf0907924de5ed1e1c.png in this picture .. caluculate m+1 ... such that am+1 < 10^-5
When you find the term that is less than \(10^{-5}\) you know the 4th decimal place, and the places before it, will not be affected anymore.
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