Question

If someone could help?? I've been working on this problem for quite some time and I can't get it!

Answer 1

i would start with exponential equation
\[y = a*b^{x}\]
then plug in 2 endpoints (1,345) and (5,604)
solve for variables a,b

Answer 2

yep... agree ^^^

Answer 3

what about finding the 9th?

Answer 4

once you have the values for a and b, plug in x=9 into the equation to get the y value.

Answer 5

but you do need to solve for a and b first.

Answer 6

so the one of them, a and b would be

(398)=(a)(b)^x or a=398 and b=1?

Answer 7

for the first "point": (1, 345)
you have: \(\large y=a\cdot b^x \) or \(\large 345=a\cdot b^1 \)

now plug in the second "point" to get another equation. from there you'll need to solve this system of equations.

Answer 8

using the second point (2, 398), what's the equation?

Answer 9

398=(a)(b)^2

Answer 10

ok... good...

345 = a*b
398 = a*b^2

so now you have a system of two equations with two unknowns. you can use substitution to solve this system...

Answer 11

a= 299.05 b= 1.15

Answer 12

ok... use those values for \(\large y=a \cdot b^x \)
now you can calculate the attendance at game #9 (x=9)...

Answer 13

thanks!

Answer 14

yw... :)