find the exact value for cos^-1(cos(-5pi/3))
Do the stuff inside the parenthesis first. cos(-5π/3) = -1/2 Then work your way outside.
x = cos^-1(-1/2) cos(x) = -1/2 x = 2π/3 and 4π/3
\[\cos^-1*\cos(5\pi/3)=1.8388\]
the answer key says the answer is pi/3 but I don't know how to do it
okay lets do it this way
Hey I miscalculated there, cos(-5π/3) = 1/2
cosx = 1/2 => x = pi/3 or -pi/3
usually for a function \(f^{-1}\circ f(x)=x\) but not in this case, because \(-\frac{5\pi}{3}\) is not in the range of \(\cos^{-1}(x)\) the range of \(\cos^{-1}(x)\) is \([0,\pi]\)
so what you are looking for is a number (angle) on the upper half of the unit circle where cosine is the same as it is at \(-\frac{5\pi}{3}\)
|dw:1363750099199:dw|
that is clearly coterminal with \(\frac{\pi}{3}\) and so that is your answer
btw the answer is NOT \(\frac{\pi}{3}\) or \(-\frac{\pi}{3}\) arccosine is a well defined function
thanks bro
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