Solve each system of equations below.

{y=x^2-2x-3
{
{6x+y=2

Question

Solve each system of equations below.

{y=x^2-2x-3
{
{6x+y=2

anonymous · Answer

I substituted the one equation in for y and tried to solve, but my answer is in coordinates and I cant remember how to do that.

campbell_st · Answer

ok.. so let y = 2 - 6x


substitute it into the 1st equation gives

$$2 - 6x = x^2 - 2x - 3$$

simplifying you get 

$$x^2 + 4x - 5 = 0$$


this can be factorised to 

(x + 5)(x -1) = 0

should be easy to solve from here

campbell_st · Answer

you have a parabola and a straight line so there are up to 2 points of intersection... 

which seems to be the case in this question.

anonymous · Answer

so that gives me the x coordinates, how do you get the y?

wikiemol · Answer

plug the x back into either of the two equations.

campbell_st · Answer

substitute the values for x into the straight line

6x + y = 2

anonymous · Answer

Ah. that makes it pretty simple...thanks guys! I missed the factoring portion. :))

campbell_st · Answer

you can choose either equation but the straight line is the easier of the 2.