Question

integral of (3x-1)/(3x+2)

Answer 1

@salimal Hi,
\(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)

For your Question, you can adjust the numerator
3x-1 as
3x-1 = 3x+2 -3
did you get this adjustment ?

Answer 2

yes

Answer 3

i get it thank you :)

Answer 4

.... now hartnn is just showing off

Answer 5

welcome ^_^
can you solve further ?
lol @amistre64 :P

Answer 6

hehe yes :P

Answer 7

great!

Answer 8

pellett i couldn`t solve it anyway :/

Answer 9

show your steps ?
we'll verify them...and spot the error if any

Answer 10

it`s ok now ..hehe i get it right..just having a bad day :p thank you :)

Answer 11

no poblem :)

Answer 12

Alternatively, you can make the substitution
\[u=3x+2\Rightarrow 3x=u-2\\
\frac{1}{3}du=dx\]
\[\int\frac{3x-1}{3x+2}dx=\frac{1}{3}\int\frac{u-2-1}{u}du\]
Then, integrate term-by-term.

Answer 13

^yes, don't forget to re substitute back u =3x+2