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Chemistry 13 Online
OpenStudy (anonymous):

When [OH-] changes from 10-9 to 10-11 in a solution: Kw = [H+][OH-] What is the [H+] after the change?

OpenStudy (anonymous):

@KonradZuse

OpenStudy (konradzuse):

Sorry, I am not good with Chem :(

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@ajprincess

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

@Preetha

OpenStudy (anonymous):

@JFraser

OpenStudy (jfraser):

since [H+]*[OH-] must always equal Kw = 1x10^(-14), then you can find the concentration of [H+]

OpenStudy (anonymous):

how do I find the concentration?

OpenStudy (anonymous):

???

OpenStudy (jfraser):

the problem tells you the conentration of OH is changing from 1*10^(-9) to 1*10^(-11)

OpenStudy (anonymous):

yes

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