Question

Multiply. State any excluded values.

Answer 1

find a common denominator first
then multiply that out to each part of the equation
then see if you can cancel out
then combine the terms

Answer 2

Oooh, how do I find a common denominator with variables involved?

Answer 3

well in this case you can just multiply the two denominators together\[\frac{ q+2 }{ q+2 }(\frac{ q+5 }{ -3 }) \times \frac{ -3 }{ -3 }(\frac{-3q }{ q+2 })\]

Answer 4

Is there where I cancel out now?

Answer 5

if terms match up, yes! cancel them out

Answer 6

Uhmmmmmmmmmmmmm are you talking about canceling out these?

Answer 7

well lets multiply it out first

Answer 8

3q + 6 / 3q + 6?

Answer 9

\[\frac{ (q+2)(q+5) }{ -3(q+2) }\times \frac{ -9q }{ -3(q+2) }=\frac{ -9q(q+2)(q+5) }{ -3(q+2) }\]

Answer 10

then we can simplify this down to \[-\frac{ q(q+5) }{ (q+2) }\]

Answer 11

but im sorry it was a bit confusing i actually shouldn't have calculated it out for you because i canceled when i did the common denominator.

Answer 12

These are the first two answer choices, the last two are similar to it so I'm still confused with what you're doing. and it's ok :b

Answer 13

alright, can you show me the choices ?

Answer 14

\[\frac{ q+5 }{ -3 } \times \frac{ -3q }{ q+2 }\] Answer choice A

Answer 15

I mean that's the equation e.e here's the asnwers under this post v.V

Answer 16

A. \[\frac{ -3q ^{2} - 15q }{ -3 } ; where q \neq 3\]

Answer 17

B. \[\frac{ -3q - 15 q ^{2} }{ 2q-6 } ; where q \neq 3\]

Answer 18

C. \[\frac{ q ^{2} - 15q }{ -3q } ; where q \neq 0\]

Answer 19

D. \[\frac{ -3q ^{2} - 15q }{ -3q-6 } ; where q \neq -2\]

Answer 20

@sjerman1

Answer 21

D. @AngelCriner

Answer 22

\[\frac{ -3q(q+5) }{ -3(q+2) }=\frac{ -3q^2-15q }{ -3q-6 };q \neq-2\]

Answer 23

Thank you