Question

Simplify:

X^2+13x+40
------------
X^2+6x-16


A. X+5
-----
X+2

B. X+5
-----
X-2

C. X+5
-----
X+8

D. X+8
-----
X-2

E. X-5
-----
X-2

Answer 1

you need to factor them out as in (X+a number)*(X+a number)
To do this you need to find two numbers that when you add the give you 13 and when you multiply they give you 40

Answer 2

then the same to the bottom
to that add to 6 and multiply to -16
hint one of the numbers will be negative

Answer 3

its 6x
and 16

so it would be 6x minus 16

Answer 4

and then 13x
and 40

13x plus 40

Answer 5

not quite, forget about the x's
the formula is (x+a)(x+b)= x^2+(a+b)x+ab
so what we are looking at is the (a+b)=13
and A*B= 40

Answer 6

Okay I think I get what you're saying now

Answer 7

The denominator is the same
A+B= 6
A*B= -16
what numbers did you find?

Answer 8

Well for the 13 and 40 one, I found that 8 plus 5 equaled 13 and 5x8 equaled 40

Answer 9

@garrett_payne

Answer 10

8 and -2
kinda tricky

Answer 11

Yeah I couldn't figure out what it was

Answer 12

So what would I do ext @garrett_payne

Answer 13

next*

Answer 14

what do you have now?

Answer 15

(x+5)(x+8)= x^2+(8+-2)x+8(-2)

??

Answer 16

\[((X+8)*(X+5))/ (X+8)*(X-2)\]
do you see anything in common?
Similar terms cancel out

Answer 17

Cancel out the 8

Answer 18

kinda, cancel out (x+8)

you are left with
(X+5)/(X-2)

Answer 19

Yeah thats what I meant

Answer 20

So it would be B right?

Answer 21

(x+5)(x+8)= x^2+(8+-2)x+8(-2)
This is not correct as the denominator should be in the
(X+a)(X+b) form
like you did in the numerator

Answer 22

oh ok

Answer 23

there you go, done
Yes, B

Answer 24

Cool Thanks :)