a triangle has an area of 75 square centimeters. if the base and height have equal length what is this length? round to the nearest tenth if necessary.
The equation for the area of a triangle is \[A = 1/2 bh\] So set up that equation with the values you are given such that \[75=1/2 (2b)\] Since both base and height are equal you can simplify b*h to 2b or 2h and then just solve for the variable.
Area=(1/2)*base*height base=length, so Area= (1/2)*length*length = 75 cm^2 solve for length length*length=2*75 cm^2 so length=sqrt(150 cm^2)
im still confused
no, it isn't 2b, it is b^2 or l^2
^what he said, careless mistake :p sorry
how do i set up the problem?
Area=(1/2)*base*height base=length, so Area= (1/2)*length*length = 75 cm^2 solve for length length*length=2*75 cm^2 so length=sqrt(150 cm^2) length = 150^(1/2) cm
Use the information you are given and plug it into the equation for a triangle\[A = \frac{ 1 }{ 2 } base * height\]and since the base and height are equal you can simplify it to \[75 = \frac{ 1 }{ 2 } * x^2\] and solve for x.
never mind i got the answer
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